陳鍾誠

Version 1.0

Tex Test

$P(X=k) = (1-p)^{k-1} p = q^{k-1} p$

$P(X=k) = (1-p)^{k-1} p = q^{k-1} p$

$P(X=k) = (1-p)^{k-1} p = q^{k-1} p$

$P(X=k) = (1-p)^{k-1} p = q^{k-1} p$


 Edit on GitHub